What would be the ratio of the root mean squa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The root mean square velocity $(u_{rms})$ is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.For hydrogen $(H_2)$ at $T_1 = 50 \ K$ and mola

Vedclass · Accepted Answer

$1/1$

Vedclass · Answer

(A) The root mean square velocity $(u_{rms})$ is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.For hydrogen $(H_2)$ at $T_1 = 50 \ K$ and molar mass $M_1 = 2 \ g/mol$:$u_{H_2} = \sqrt{\frac{3R(50)}{2}}$.For oxygen $(O_2)$ at $T_2 = 800 \ K$ and molar mass $M_2 = 32 \ g/mol$:$u_{O_2} = \sqrt{\frac{3R(800)}{32}}$.The ratio is $\frac{u_{H_2}}{u_{O_2}} = \sqrt{\frac{50}{2} 	imes \frac{32}{800}} = \sqrt{25 	imes \frac{1}{25}} = \sqrt{1} = 1/1$.

What would be the ratio of the root mean square velocity of hydrogen gas at $50 \ K$ and that of oxygen at $800 \ K$?

Similar Questions

At $27 \ ^oC$,the ratio of $rms$ velocities of ozone to oxygen is

The average speed of a gas molecule is $400 \, m/s$. Calculate its $rms$ speed at the same temperature in $m/s$.

The $r.m.s.$ velocity of a certain gas is $v$ at $300 \ K$. The temperature,at which the $r.m.s.$ velocity becomes double,is ............... $K$.

For $1 \ mol$ of a gas,the average kinetic energy is $E$. Then the root mean square velocity $U_{rms}$ of the gas is:

One way to decrease the average speed of molecules of an ideal gas is ............. .

Vedclass Test Series

Exam Paper Generator

Online Exam Module