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(B) Using the ideal gas equation $PV = nRT$,the number of moles $n$ is given by $n = \frac{PV}{RT}$.For container $A$: $P_A = 2P$,$V_A = 2V$,$T_A = 2T

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$2 : 1$

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(B) Using the ideal gas equation $PV = nRT$,the number of moles $n$ is given by $n = \frac{PV}{RT}$.For container $A$: $P_A = 2P$,$V_A = 2V$,$T_A = 2T$. Thus,$n_A = \frac{(2P)(2V)}{R(2T)} = 2 \frac{PV}{RT}$.For container $B$: $P_B = P$,$V_B = V$,$T_B = T$. Thus,$n_B = \frac{PV}{RT}$.The ratio of the number of molecules (which is proportional to the number of moles) is $\frac{n_A}{n_B} = \frac{2(PV/RT)}{(PV/RT)} = 2 : 1$.

Containers $A$ and $B$ contain the same gas. The pressure,volume,and temperature of the gas in $A$ are twice the corresponding values of the gas in $B$. The ratio of the number of molecules of gas in $A$ to that in $B$ is ...

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