Calculate the temperature of $4.0 \, mol$ of a gas occupying $5 \, dm^{3}$ at $3.32 \, bar$.
$(R = 0.083 \, bar \, dm^{3} \, K^{-1} \, mol^{-1})$
$(R = 0.083 \, bar \, dm^{3} \, K^{-1} \, mol^{-1})$
(N/A) Given:
$n = 4.0 \, mol$
$V = 5 \, dm^{3}$
$p = 3.32 \, bar$
$R = 0.083 \, bar \, dm^{3} \, K^{-1} \, mol^{-1}$
The temperature $(T)$ can be calculated using the ideal gas equation:
$p V = n R T$
Rearranging for $T$:
$T = \frac{p V}{n R}$
Substituting the values:
$T = \frac{3.32 \times 5}{4 \times 0.083}$
$T = \frac{16.6}{0.332}$
$T = 50 \, K$
Thus,the temperature of the gas is $50 \, K$.
$n = 4.0 \, mol$
$V = 5 \, dm^{3}$
$p = 3.32 \, bar$
$R = 0.083 \, bar \, dm^{3} \, K^{-1} \, mol^{-1}$
The temperature $(T)$ can be calculated using the ideal gas equation:
$p V = n R T$
Rearranging for $T$:
$T = \frac{p V}{n R}$
Substituting the values:
$T = \frac{3.32 \times 5}{4 \times 0.083}$
$T = \frac{16.6}{0.332}$
$T = 50 \, K$
Thus,the temperature of the gas is $50 \, K$.
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