What is the number of lone pairs of electrons | vedclass

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(A) The number of lone pairs on the central atom $Xe$ can be determined using the formula: $	ext{Lone pairs} = \frac{1}{2} (V - B)$,where $V$ is the

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$3, 2$ and $1$

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(A) The number of lone pairs on the central atom $Xe$ can be determined using the formula: $	ext{Lone pairs} = \frac{1}{2} (V - B)$,where $V$ is the number of valence electrons of the central atom ($8$ for $Xe$) and $B$ is the number of bonding pairs (number of $F$ atoms attached).						$	ext{Compound}$			$	ext{Lone pairs on } Xe$							$XeF_2$			$\frac{1}{2}(8-2) = 3$							$XeF_4$			$\frac{1}{2}(8-4) = 2$							$XeF_6$			$\frac{1}{2}(8-6) = 1$			Thus,the number of lone pairs are $3, 2$,and $1$ respectively.

List-$I$	List-$II$
$I$. $XeF_4$	$A$. See-saw
$II$. $I_3^-$	$B$. Tetrahedral
$III$. $XeO_2F_2$	$C$. Bond angle $90^o$
$IV$. $SO_4^{2-}$	$D$. Linear

What is the number of lone pairs of electrons on the central atom in $XeF_2, XeF_4$,and $XeF_6$ molecules,respectively?

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Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists.

List-$I$ List-$II$

$I$. $XeF_4$ $A$. See-saw

$II$. $I_3^-$ $B$. Tetrahedral

$III$. $XeO_2F_2$ $C$. Bond angle $90^o$

$IV$. $SO_4^{2-}$ $D$. Linear

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