Bromine trifluoride autoionizes to form BrF_2 | vedclass

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Question

(A) For $BrF_2^+$: The central $Br$ atom has $7$ valence electrons. It forms $2$ bonds with $F$ atoms and loses $1$ electron to become a cation,leavin

Vedclass · Accepted Answer

bent,square planar

Vedclass · Answer

(A) For $BrF_2^+$: The central $Br$ atom has $7$ valence electrons. It forms $2$ bonds with $F$ atoms and loses $1$ electron to become a cation,leaving $3$ lone pairs. However,considering $VSEPR$ theory for $AX_2E_2$ type (where $X=2$ bonding pairs and $E=2$ lone pairs),the geometry is bent.For $BrF_4^-$: The central $Br$ atom has $7$ valence electrons,gains $1$ electron from the anion formation,and forms $4$ bonds with $F$ atoms,leaving $2$ lone pairs. This corresponds to $AX_4E_2$ type,which results in a square planar structure.

Bromine trifluoride autoionizes to form $BrF_2^+$ and $BrF_4^-$. The shapes of the cation and anion are respectively . . . . . . ,and . . . . . . .

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