$SnCl_2$ acts as a reducing agent because:
- A$SnCl_2$ can accept electrons readily
- B$Sn^{2+}$ is more stable than $Sn^{4+}$
- C$Sn^{4+}$ is more stable than $Sn^{2+}$
- D$Sn^{2+}$ can be easily converted to metallic tin
Explore More
Similar Questions
Which of the following compounds of lead is used in the match industry?
Easy
View SolutionIdentify $(P)$ and $(Q)$ in the following reaction:
$2 CH_3 Cl + Si$ $\xrightarrow[570 \ K]{\text{Cu powder}} (P)$ $\xrightarrow{H_2 O} (Q)$ $\longrightarrow \text{Straight chain polymer}$
$2 CH_3 Cl + Si$ $\xrightarrow[570 \ K]{\text{Cu powder}} (P)$ $\xrightarrow{H_2 O} (Q)$ $\longrightarrow \text{Straight chain polymer}$
The stability of dihalides of $Si, Ge, Sn$ and $Pb$ follows the sequence.
The main reason that $SiCl_{4}$ is easily hydrolysed as compared to $CCl_{4}$ is that
Producer gas is a mixture of
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo