Identify $(P)$ and $(Q)$ in the following reaction:
$2 CH_3 Cl + Si$ $\xrightarrow[570 \ K]{\text{Cu powder}} (P)$ $\xrightarrow{H_2 O} (Q)$ $\longrightarrow \text{Straight chain polymer}$

  • A
    $P: (CH_3)_3 SiCl$
    $Q: (CH_3)_3 SiOH$
  • B
    $P: (CH_3)_2 SiCl_2$
    $Q: (CH_3)_2 Si(OH)_2$
  • C
    $P: (CH_3)_2 SiCl_2$
    $Q: (CH_3)_2 Si(OH)Cl$
  • D
    $P: (CH_3)_2 SiCl_2$
    $Q: (CH_3)_2 SiO$

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Evaluate the following statements related to group $14$ elements for their correctness.
$(A)$ Covalent radius decreases down the group from $C$ to $Pb$ in a regular manner.
$(B)$ Electronegativity decreases from $C$ to $Pb$ down the group gradually.
$(C)$ Maximum covalence of $C$ is $4$ whereas other elements can expand their covalence due to presence of $d$ orbitals.
$(D)$ Heavier elements do not form $p\pi-p\pi$ bonds.
$(E)$ Carbon can exhibit negative oxidation states.
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