$12 \ g$ of a nonvolatile solute dissolved in $108 \ g$ of water produces the relative lowering of vapour pressure of $0.1$. The molecular mass of the solute is

The vapour pressure of pure water is $92.5 \ mm$ at $300 \ K$. The vapour pressure of $1 \ molal$ solution of $X$ in water is :-

$A$ mixture of $3.0 \ mol$ of $Na_2O$ and $1.5 \ mol$ of $KO_2$ is dissolved in $1000 \ mL$ of water. The vapour pressure of the solution in $Torr$,at $100^{\circ}C$ is:

Relative lowering of vapour pressure of a dilute solution is $0.5$. What is the mole fraction of the non-volatile solute?

At $298 \ K$,the vapour pressure of pure water is $25 \ torr$. The vapour pressure of water,when $12 \ g$ of urea (molar mass,$60 \ g \ mol^{-1}$) and $36 \ g$ of glucose (molar mass,$180 \ g \ mol^{-1}$) is dissolved in $100 \ g$ of water at the same temperature (in $torr$) is

When $18 \ g$ of glucose $(C_6H_{12}O_6)$ is added to $178.2 \ g$ of water,the vapour pressure of the aqueous solution at $100 \ ^\circ C$ is .......... $torr$.