HCequiv CH xrightarrow[HgSO_4]{H_2SO_4} (A) x | vedclass

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Question

(B) The reaction proceeds as follows:$1$. Acetylene $(HC\equiv CH)$ undergoes hydration in the presence of $HgSO_4$ and $H_2SO_4$ to form acetaldehyde

Vedclass · Accepted Answer

Alanine

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(B) The reaction proceeds as follows:$1$. Acetylene $(HC\equiv CH)$ undergoes hydration in the presence of $HgSO_4$ and $H_2SO_4$ to form acetaldehyde $(CH_3CHO)$ as product $(A)$.$2$. Acetaldehyde $(CH_3CHO)$ reacts with $NH_3$ and $HCN$ (Strecker synthesis) followed by hydrolysis $(H_3O^{\oplus})$ to form the amino acid alanine $(CH_3-CH(NH_2)-COOH)$ as product $(B)$.

$HC\equiv CH$ $\xrightarrow[HgSO_4]{H_2SO_4} (A)$ $\xrightarrow[(1) NH_3 + HCN]{(2) H_3O^{\oplus}} (B);$ The product $(B)$ of the given reaction is:

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