Ph-NO_2 + Et-Cl xrightarrow{AlCl_3} (A),Produ | vedclass

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(B) The reaction given is a Friedel-Crafts alkylation reaction. Nitrobenzene $(Ph-NO_2)$ contains a strongly electron-withdrawing $-NO_2$ group. This

Vedclass · Accepted Answer

no-reaction

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(B) The reaction given is a Friedel-Crafts alkylation reaction. Nitrobenzene $(Ph-NO_2)$ contains a strongly electron-withdrawing $-NO_2$ group. This group deactivates the benzene ring towards electrophilic aromatic substitution. Furthermore,the lone pair on the nitrogen atom of the $-NO_2$ group coordinates with the Lewis acid catalyst $AlCl_3$,which further deactivates the ring. Therefore,nitrobenzene does not undergo Friedel-Crafts alkylation. Thus,there is no reaction.

$Ph-NO_2 + Et-Cl \xrightarrow{AlCl_3} (A)$,Product $(A)$ of the given reaction is

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