Identify the product when chlorobenzene is heated with nitrating mixture.

  • A
    Only $1-$chloro$-4-$nitrobenzene
  • B
    Only $1-$chloro$-2-$nitrobenzene
  • C
    Mixture of $1-$chloro$-2-$nitrobenzene and $1-$chloro$-4-$nitrobenzene
  • D
    $2,4,6-$trinitrochlorobenzene

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Similar Questions

In chlorobenzene,the $-Cl$ group is deactivating; however,it still undergoes electrophilic aromatic substitution reactions. Column-$(I)$ contains the reagents and Column-$(II)$ contains the products. Match Column-$(I)$ with Column-$(II)$.
| Column-$(I)$ (Reagents) | Column-$(II)$ (Products) |
| :--- | :--- |
| $(A)$ $Cl_2$ / anhydrous $AlCl_3$ | $(i)$ $1$-chloro-$2$-methylbenzene + $1$-chloro-$4$-methylbenzene |
| $(B)$ conc. $HNO_3$ + conc. $H_2SO_4$ | $(ii)$ $2$-chlorobenzenesulfonic acid + $4$-chlorobenzenesulfonic acid |
| $(C)$ conc. $H_2SO_4$ and heat | $(iii)$ $1,2$-dichlorobenzene + $1,4$-dichlorobenzene |
| $(D)$ $CH_3COCl$ in presence of anhydrous $AlCl_3$ | $(iv)$ $2$-chloroacetophenone + $4$-chloroacetophenone |
| | $(v)$ $1$-chloro-$2$-nitrobenzene + $1$-chloro-$4$-nitrobenzene |

When nitrobenzene is reacted with $Br_2$ in the presence of $FeBr_3$,the major product formed is $m$-bromonitrobenzene. This is because:

$A$ group which deactivates the benzene ring towards electrophilic substitution but which directs the incoming group principally to the $o-$ and $p-$ positions is

Identify compounds $A$ and $E$ in the following reaction sequence.

"The presence of an electron-withdrawing group $\left( -NO_2 \right)$ at the ortho and para positions in haloarenes increases the reactivity of haloarenes towards nucleophilic substitution reactions." Prove this with an example.

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