(A) xrightarrow{NH_2OH} (B) xrightarrow{H_2SO | vedclass

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Question

(A) is acetone $(CH_3COCH_3)$,which has a molecular weight of $58 \ g/mol$. $(A) \xrightarrow{NH_2OH} (B)$ (acetone oxime,$CH_3C(=NOH)CH_3$). $(B) \xr

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$58$

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(A) is acetone $(CH_3COCH_3)$,which has a molecular weight of $58 \ g/mol$. $(A) \xrightarrow{NH_2OH} (B)$ (acetone oxime,$CH_3C(=NOH)CH_3$). $(B) \xrightarrow{H_2SO_4} (C)$ ($N$-methylacetamide,$CH_3CONHCH_3$ via Beckmann rearrangement). $(C) \xrightarrow{H_3O^{\oplus}} (D) + (E)$ (acetic acid,$CH_3COOH$ and methylamine,$CH_3NH_2$). $(E) \xrightarrow{CHCl_3, KOH} CH_3NC$ (carbylamine test confirms methylamine). $(D) \xrightarrow{SOCl_2} (F)$ (acetyl chloride,$CH_3COCl$). $(F) \xrightarrow{(i) PhMgBr (excess) (ii) H^{\oplus}} (G)$ ($1$,$1$-diphenylethanol,$Ph_2C(OH)CH_3$). $(G) \xrightarrow[\Delta]{H^{\oplus}} (H)$ ($1$,$1$-diphenylethene,$Ph_2C=CH_2$). $(H) \xrightarrow{CH_2I_2, Zn/Cu} 	ext{1,1-diphenylcyclopropane}$ (Simmons-Smith reaction). Thus,$(A)$ is acetone,$C_3H_6O$,molecular weight $= 3 	imes 12 + 6 	imes 1 + 16 = 58$.

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