(A) xrightarrow[(1) text{ excess } CH_3I/K_2C | vedclass

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(C) The reaction sequence is the Hofmann exhaustive methylation,which is used to determine the structure of amines by converting them into alkenes thr

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$4-$Methylpiperidine

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(C) The reaction sequence is the Hofmann exhaustive methylation,which is used to determine the structure of amines by converting them into alkenes through quaternary ammonium salts.Starting from $(A)$,the first sequence of reactions produces $(B)$,and the second sequence produces $H_2C=CH-CH(CH_3)-CH=CH_2$ ($3$-methyl$-1,4-$pentadiene).By analyzing the product $H_2C=CH-CH(CH_3)-CH=CH_2$,it can be traced back to the cyclic amine $4-$methylpiperidine.In $4-$methylpiperidine,the nitrogen is at position $1$ and the methyl group is at position $4$.Upon exhaustive methylation and elimination,the ring opens to form the observed diene product.Therefore,$(A)$ is $4-$methylpiperidine.

$(A)$ $\xrightarrow[(1) \text{ excess } CH_3I/K_2CO_3, (2) \text{ } Ag_2O/H_2O, (3) \text{ } \Delta]{} (B)$ $\xrightarrow[(i) \text{ excess } CH_3I/K_2CO_3, (ii) \text{ } Ag_2O, (iii) \text{ } \Delta]{} H_2C=CH-CH(CH_3)-CH=CH_2$. Identify $(A)$.

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