In the following reaction,the product (A) is: | vedclass

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(D) The reaction between benzenediazonium chloride and aniline in a weakly acidic medium $(pH \approx 4-5)$ is an electrophilic aromatic substitution

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$C_6H_5-N=N-(C_6H_4)-NH_2$ (para)

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(D) The reaction between benzenediazonium chloride and aniline in a weakly acidic medium $(pH \approx 4-5)$ is an electrophilic aromatic substitution reaction known as coupling reaction. In this reaction,the diazonium cation acts as an electrophile and attacks the electron-rich ring of aniline. Since the $-NH_2$ group is a strong ortho/para directing group,and due to steric hindrance at the ortho position,the electrophile preferentially attacks the para position of aniline to form $p$-aminoazobenzene,which is a yellow dye.

In the following reaction,the product $(A)$ is:

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The reaction sequence is given as follows:
$CH_3-CO-CH_2-CH_2-CO-CH_3$ $\xrightarrow[(NH_4)_2CO_3]{\Delta} (A)$ $\xrightarrow[CCl_3CO_2Na]{\Delta} (B)$
Product $(B)$ of the above reaction is:

$CH_3NH_2 + CHCl_3 + 3KOH \rightarrow X + Y + 3H_2O$;
Compounds $X$ and $Y$ are:

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