CH_3-CH(NH_2)-CH_3 xrightarrow{HNO_2} A xrigh | vedclass

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(D) Isopropylamine $(CH_3-CH(NH_2)-CH_3)$ reacts with nitrous acid $(HNO_2)$ to form Isopropyl alcohol $(A)$.The oxidation of Isopropyl alcohol,which

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$CH_3-C(CH_3)(OH)-CH_3$

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(D) Isopropylamine $(CH_3-CH(NH_2)-CH_3)$ reacts with nitrous acid $(HNO_2)$ to form Isopropyl alcohol $(A)$.The oxidation of Isopropyl alcohol,which is a secondary alcohol,yields Acetone $(B)$.Acetone then reacts with the Grignard reagent Methyl magnesium iodide $(CH_3MgI)$,followed by hydrolysis,to produce tert-Butyl alcohol $(C)$.Reaction sequence:$CH_3-CH(NH_2)-CH_3$ $\xrightarrow{HNO_2} CH_3-CH(OH)-CH_3 (A)$ $\xrightarrow{	ext{oxidation}} CH_3-CO-CH_3 (B)$ $\xrightarrow{(i) CH_3MgI, (ii) H_2O} CH_3-C(CH_3)(OH)-CH_3 (C)$.

$CH_3-CH(NH_2)-CH_3$ $\xrightarrow{HNO_2} A$ $\xrightarrow{\text{oxidation}} B$ $\xrightarrow[(ii) H_2O]{(i) CH_3MgI} C$. $C$ is:

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