Number of sigma and pi bonds in benzophenone | vedclass

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(D) The chemical formula of benzophenone is $(C_6H_5)_2CO$.In the structure,there are two phenyl rings attached to a carbonyl group $(C=O)$.Each pheny

Vedclass · Accepted Answer

$25, 7$

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(D) The chemical formula of benzophenone is $(C_6H_5)_2CO$.In the structure,there are two phenyl rings attached to a carbonyl group $(C=O)$.Each phenyl ring $(C_6H_5)$ contains $6$ $C-C$ bonds (including $3$ double bonds) and $5$ $C-H$ bonds.Total $\sigma$ bonds in two phenyl rings = $2 	imes (6 + 5) = 22$.There are $2$ $C-C$ single bonds connecting the carbonyl carbon to the phenyl rings.There is $1$ $C-O$ $\sigma$ bond in the carbonyl group.Total $\sigma$ bonds = $22 + 2 + 1 = 25$.Total $\pi$ bonds = $2 	imes 3$ (from two benzene rings) + $1$ (from $C=O$ bond) = $6 + 1 = 7$.Thus,there are $25$ $\sigma$ bonds and $7$ $\pi$ bonds.

Column-$I$ (Reactants)	Column-$II$ (Major Product)
$A$. $HCHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$i$. $C_6H_5CHOHCH_3$
$B$. $C_6H_5CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$ii$. $(CH_3)_3COH$
$C$. $CH_3COCH_3 \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iii$. $CH_3CHOHCH_3$
$D$. $CH_3CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iv$. $CH_3CH_2OH$

Number of $\sigma$ and $\pi$ bonds in benzophenone is

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