CH_3CH_2OH + HX xrightarrow{ZnX_2} CH_3CH_2 - | vedclass

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(B) The reaction of alcohols with hydrogen halides $(HX)$ in the presence of $ZnX_2$ (Lucas reagent) follows the reactivity order of $HX$ based on the

Vedclass · Accepted Answer

$HI > HBr > HCl$

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(B) The reaction of alcohols with hydrogen halides $(HX)$ in the presence of $ZnX_2$ (Lucas reagent) follows the reactivity order of $HX$ based on the ease of bond cleavage.The bond dissociation energy of $HX$ decreases in the order $HCl > HBr > HI$.Since $HI$ has the lowest bond dissociation energy,the $H-I$ bond is the easiest to break,making $HI$ the most reactive.Therefore,the correct order of reactivity is $HI > HBr > HCl$.

$CH_3CH_2OH + HX \xrightarrow{ZnX_2} CH_3CH_2 - X + H_2O$. What is the reactivity order of $HX$?

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