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Explain why are low molecular mass alcohols soluble in water?
Medium
View SolutionMatch the compounds in Column-$I$ with their major dehydration products in Column-$II$.
Column-$I$ (Compound) Column-$II$ (Major Product) $A$. $1$-Methylcyclohexanol $i$. $1$-Methylcyclohexene $B$. Butan-$1$-ol $ii$. But-$1$-ene $C$. tert-Butyl alcohol $iii$. Isobutylene $D$. Butan-$2$-ol $iv$. But-$2$-ene
| Column-$I$ (Compound) | Column-$II$ (Major Product) |
| $A$. $1$-Methylcyclohexanol | $i$. $1$-Methylcyclohexene |
| $B$. Butan-$1$-ol | $ii$. But-$1$-ene |
| $C$. tert-Butyl alcohol | $iii$. Isobutylene |
| $D$. Butan-$2$-ol | $iv$. But-$2$-ene |
Medium
View SolutionThe reaction of $2$-cyclohexylethanol with $H^{\oplus}$ and $\Delta$ yields a major product $A$. Identify $A$.
Difficult
View SolutionChloroform can be obtained from
Difficult
View SolutionProduct $(C)$ is
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