Alkene xrightarrow{text{Ozonolysis}} 2,6-hept | vedclass

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(C) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the formation of two carbonyl groups at the cleavage sites. For cyclic

Vedclass · Accepted Answer

$1,2-$dimethylcyclopentene

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(C) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the formation of two carbonyl groups at the cleavage sites. For cyclic alkenes,ozonolysis results in the opening of the ring to form a dicarbonyl compound. $2,6-$heptanedione is a seven-carbon chain with ketone groups at positions $2$ and $6$. This indicates that the original alkene was a six-membered ring with two methyl groups attached to the double-bonded carbons,specifically $1,2-$dimethylcyclopentene. When $1,2-$dimethylcyclopentene undergoes ozonolysis,the double bond breaks,resulting in a seven-carbon chain with ketones at the ends of the original double bond,which corresponds to $2,6-$heptanedione.

Alkene $\xrightarrow{\text{Ozonolysis}} 2,6-$heptanedione. Find the alkene.

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