V_o and V_E represent the velocities,mu_o and | vedclass

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(C) In double refraction,an incident light ray splits into two rays: the ordinary ray ($O$-ray) and the extraordinary ray ($E$-ray).For a negative uni

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$V_o \le V_E, \mu_o \ge \mu_E$ if the crystal is calcite

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(C) In double refraction,an incident light ray splits into two rays: the ordinary ray ($O$-ray) and the extraordinary ray ($E$-ray).For a negative uniaxial crystal like calcite,the velocity of the extraordinary ray $(V_E)$ is greater than the velocity of the ordinary ray $(V_o)$,which implies $\mu_E  \mu_E$.Thus,for calcite,$V_o  \mu_E$.For a positive uniaxial crystal like quartz,the velocity of the extraordinary ray $(V_E)$ is less than the velocity of the ordinary ray $(V_o)$,which implies $\mu_E > \mu_o$.Therefore,option $(c)$ correctly describes the relationship for calcite.

$V_o$ and $V_E$ represent the velocities,$\mu_o$ and $\mu_E$ represent the refractive indices of ordinary and extraordinary rays for a doubly refracting crystal. Then:

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