"Isoelectronic molecules and ions have identical bond orders." Explain by examples.
Bond order in Isoelectronic molecules/ions :
If two or more diatomic molecule or ion are isoelectronic so its bond order is same. Example-$1$: $\mathrm{F}_{2}$ and $\mathrm{O}_{2}^{-2}$ both have same $18$ electrons and bond order is also same $1$ . $\mathrm{F}_{2}: \mathrm{F}-\mathrm{F}$ and $\mathrm{O}_{2}^{-2}(\mathrm{O}-\mathrm{O})^{2-}$
Example-$2$: $\mathrm{N}_{2}, \mathrm{CO}$ and $\mathrm{NO}^{+}$are isoelectronic and containing $14$ electron and triple bond in it.
Molecule/ion | $\mathrm{N}_{2}$ | $\mathrm{CO}$ | $\mathrm{NO}^{+}$ |
Bond structure | $\mathrm{N} \equiv \mathrm{N}$ | $\mathrm{C} \equiv \mathrm{O}$ | $\mathrm{N} \equiv \mathrm{O}^{+}$ |
The pairs of species of oxygen and their magnetic behaviour are noted below. Which of the following presents the correct description ?
Which of the following is paramagnetic
What is meant by the term bond order ? Calculate the bond order of: $N _{2}, O _{2}, $ $O _{2}^{+}$ and $O _{2}^{-}$
Match List $I$ with List $II$ :
List $I$ (Molecule Species) |
List $I$ ( Property Shape ) |
$A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ | $I$ Paramagnetic |
$B$ $NO$ | $II$ Diamagnetic |
$C$ $\mathrm{NO}_2^{-}$ | $III$ Tetrahedral |
$D$ $\mathrm{I}_3^{-}$ | $IV$ Linear |
Choose the correct answer from the options given below :
In which of the following transformations, the bond order has increased and the magnetic behaviour has changed?