Classification Questions in English

(B) The options $Birds$,$Aeroplane$,and $Kite$ are all capable of flying in the sky. $Fish$ is the odd one out because it is an aquatic animal that lives and swims in water,not in the sky.

(C) The symbols $-$,$+$,and $=$ are standard mathematical operators used for subtraction,addition,and equality,respectively. The symbol $@$ is not a standard mathematical operator,making it the odd one out.

(A) Black pepper,chilli,and coriander are all classified as spices derived from plants. Salt is a mineral compound $(NaCl)$ and is not a spice. Therefore,salt is the odd one out.

(D) Mica,Zinc,and Iron are solids at room temperature,whereas Chlorine is a gas at room temperature. Therefore,Chlorine is the odd one out.

(D) We analyze the divisibility of each number by $7$:
$63 = 7 \times 9$
$84 = 7 \times 12$
$91 = 7 \times 13$
$65 = 7 \times 9 + 2$
Since $63$,$84$,and $91$ are divisible by $7$,while $65$ is not,$65$ is the odd one out.

(B) Analyze the given numbers:
$39 = 3 \times 13$
$27 = 3^3$
$48 = 3 \times 16$
$42 = 3 \times 14$
Among the given options,$27$ is a perfect cube $(3^3 = 27)$,whereas $39$,$48$,and $42$ are not perfect cubes. Therefore,$27$ is the odd one out.

(D) In options $A$,$B$,and $C$,the words are antonyms (opposites) of each other.
Work is the opposite of Leisure.
Day is the opposite of Night.
Expedite (to speed up) is the opposite of Procrastinate (to delay).
However,in option $D$,'Frequently' and 'Always' are not antonyms; they both indicate high frequency,making them synonyms or related in degree.
Therefore,$D$ is the odd one out.

(D) The months $March$,$January$,and $July$ each have $31$ days.
However,the month $June$ has only $30$ days.
Therefore,$June$ is the odd one out.

(C) In the English alphabet,pairs of letters are considered opposite if their positions from the start and end are the same.
$B$ is the $2^{nd}$ letter from the start,and $Y$ is the $2^{nd}$ letter from the end. Thus,$(B, Y)$ is an opposite pair.
$L$ is the $12^{th}$ letter from the start,and $O$ is the $12^{th}$ letter from the end. Thus,$(L, O)$ is an opposite pair.
$G$ is the $7^{th}$ letter from the start,and $T$ is the $7^{th}$ letter from the end. Thus,$(G, T)$ is an opposite pair.
$E$ is the $5^{th}$ letter from the start,while $W$ is the $4^{th}$ letter from the end. Therefore,$(E, W)$ is not an opposite pair.
Hence,$EW$ is the odd one out.

(D) Analyze the relationship between the numbers in each pair:
$25 = 5^{2}$
$16 = 4^{2}$
$144 = 12^{2}$
$64 = 8^{2}$,but the option gives $64-7$.
In all other options,the first number is the square of the second number. In option $D$,$64$ is the square of $8$,not $7$. Therefore,$64-7$ is the odd one out.

(D) The numbers $28$,$42$,and $35$ are all divisible by $7$ ($28 = 7 \times 4$,$42 = 7 \times 6$,$35 = 7 \times 5$).
$65$ is not divisible by $7$ $(65 = 7 \times 9 + 2)$.
Therefore,$65$ is the odd one out.

(D) Analyze the relationship between the number and the letter in each option based on the alphabetical position $(A=1, B=2, C=3, D=4, E=5, F=6, G=7, H=8, I=9, J=10, K=11, L=12)$:
$A) 25-E: 5^2 = 25$ (Correct,$E$ is the $5^{th}$ letter).
$B) 16-D: 4^2 = 16$ (Correct,$D$ is the $4^{th}$ letter).
$C) 144-L: 12^2 = 144$ (Correct,$L$ is the $12^{th}$ letter).
$D) 64-G: 8^2 = 64$,but $G$ is the $7^{th}$ letter,not the $8^{th}$ letter ($H$ is the $8^{th}$ letter).
Therefore,$64-G$ is the odd one out because it does not follow the pattern where the number is the square of the alphabetical position of the letter.

(B) In options $A$,$C$,and $D$,the group consists of a person who operates a transport vehicle,a person who travels in it,and the vehicle itself. However,option $B$ consists of items that belong to the category of furniture. Therefore,$B$ is the odd one out.