Alphabet Test Questions in English

(A) Given letters are $I(1), N(2), E(3), T(4), O(5), C(6)$.
Let us test the options:
Option $A$: $2, 5, 4, 1, 6, 3$ gives $N-O-T-I-C-E$,which is a meaningful word.
Option $B$: $3, 6, 4, 1, 2, 5$ gives $E-C-T-I-N-O$,which is not a meaningful word.
Option $C$: $4, 3, 6, 5, 2, 1$ gives $T-E-C-O-N-I$,which is not a meaningful word.
Option $D$: $6, 5, 2, 3, 4, 1$ gives $C-O-N-E-T-I$,which is not a meaningful word.
Therefore,the correct combination is $2, 5, 4, 1, 6, 3$.

(C) Given letters are: $T(1), P(2), S(3), L(4), O(5), I(6)$.
Checking the options:
Option $A$: $4, 6, 2, 5, 3, 1 \rightarrow L, I, P, O, S, T$ ($LIPOST$ - Not a word).
Option $B$: $2, 5, 4, 3, 6, 1 \rightarrow P, O, L, S, I, T$ ($POLSIT$ - Not a word).
Option $C$: $2, 6, 3, 1, 5, 4 \rightarrow P, I, S, T, O, L$ ($PISTOL$ - $A$ meaningful word).
Option $D$: $3, 6, 4, 2, 5, 1 \rightarrow S, I, L, P, O, T$ ($SILPOT$ - Not a word).
Therefore,the correct combination is $2, 6, 3, 1, 5, 4$.

(B) The given letters are $M(1), F(2), I(3), A(4), N(5), E(6)$.
We need to arrange these letters to form a meaningful word.
By testing the combinations:
Option $B$ gives $2, 4, 1, 3, 5, 6$,which corresponds to $F, A, M, I, N, E$.
This forms the word $FAMINE$,which is a meaningful English word.
Therefore,the correct combination is $2, 4, 1, 3, 5, 6$.

(B) To form a meaningful word from the given letters $N(1), A(2), E(3), H(4), L(5), D(6)$:
Checking option $C$: $4, 3, 6, 5, 2, 1$ corresponds to $H, E, D, L, A, N$ (Not a word).
Checking option $B$: $4, 2, 1, 6, 5, 3$ corresponds to $H, A, N, D, L, E$,which forms the word $HANDLE$.
Therefore,the correct combination is $4, 2, 1, 6, 5, 3$.

(B) Given letters are $E(1), T(2), C(3), K(4), O(5), P(6)$.
Checking option $B$: $6, 5, 3, 4, 1, 2$ corresponds to $P, O, C, K, E, T$.
This forms the meaningful word $POCKET$.
Therefore,the correct combination is $6, 5, 3, 4, 1, 2$.

(A) The given letters are $E(1), L(2), G(3), N(4), I(5), M(6)$.
We need to arrange these letters to form a meaningful word.
By testing the combinations:
Option $C$ gives $6, 5, 3, 2, 1, 4$,which corresponds to $M, I, G, L, E, N$. This does not form a standard word.
Option $D$ gives $3, 5, 6, 2, 1, 4$,which corresponds to $G, I, M, L, E, N$. This does not form a standard word.
Let us re-examine the letters: $M, I, N, G, L, E$.
$M$ is $6$,$I$ is $5$,$N$ is $4$,$G$ is $3$,$L$ is $2$,$E$ is $1$.
Therefore,the sequence is $6, 5, 4, 3, 2, 1$.
This corresponds to option $A$.

(C) The given letters are $D(1), A(2), I(3), M(4), E(5), N(6)$.
We need to arrange these to form a meaningful word.
Testing option $C$: $4, 2, 3, 1, 5, 6$ corresponds to $M, A, I, D, E, N$,which forms the word $MAIDEN$.
Therefore,the correct combination is $4, 2, 3, 1, 5, 6$.

(C) Given letters are $R(1), E(2), S(3), T(4), L(5), U(6)$.
Checking the options:
Option $A$: $3, 4, 6, 1, 2, 5 \rightarrow S, T, U, R, E, L$ (Not a word).
Option $B$: $4, 5, 3, 2, 6, 1 \rightarrow T, L, S, E, U, R$ (Not a word).
Option $C$: $5, 6, 3, 4, 1, 2 \rightarrow L, U, S, T, R, E$ (Meaningful word: $LUSTRE$).
Option $D$: $6, 5, 2, 1, 4, 3 \rightarrow U, L, E, R, T, S$ (Not a word).
Therefore,the correct combination is $5, 6, 3, 4, 1, 2$.

(B) To determine which word can be formed,we check the frequency of letters in each option against the given set of letters: $a, a, d, e, f, g, r, s, u$.
$1$. $stagnation$: Contains '$t$','$i$','$o$','$n$' which are not in the given set.
$2$. $safeguard$: Contains '$s, a, f, e, g, u, a, r, d$'. All these letters are present in the given set $(a: 2, d: 1, e: 1, f: 1, g: 1, r: 1, s: 1, u: 1)$.
$3$. $pseudo-grade$: Contains '$p$','$o$' which are not in the given set.
$4$. $grandson$: Contains '$n$','$o$' which are not in the given set.
Therefore,the word '$safeguard$' can be formed.

(D) To determine which word can be formed,we count the frequency of each letter in the given set: $a: 2, b: 1, c: 1, i: 1, l: 2, n: 1, o: 3, r: 1, t: 1$.
Now,let's check the options:
$A) \text{collapsible}: c(1), o(1), l(2), a(1), p(1), s(2), i(1), b(1), e(1)$. The letter '$p$','$s$',and '$e$' are not in the given set.
$B) \text{locomotive}: l(1), o(2), c(1), m(1), t(1), i(1), v(1), e(1)$. The letter '$m$','$v$',and '$e$' are not in the given set.
$C) \text{colourfulnesa}: \text{Contains letters not in the set.}$
$D) \text{collaboration}: c(1), o(3), l(2), a(2), b(1), r(1), t(1), i(1), n(1)$.
Comparing the letter counts: $c(1), o(3), l(2), a(2), b(1), r(1), t(1), i(1), n(1)$. All these letters are present in the given set in the required quantities.
Therefore,the correct word is $collaboration$.

(C) The given letters are $N, U, M, K, I, P, P$.
By rearranging these letters in the proper order,we get the word $PUMPKIN$,which is the name of a vegetable.
The word is $P-U-M-P-K-I-N$.
The last letter of the word $PUMPKIN$ is $N$.

(B) The given letters are $N, A, B, M, O, D, I, N, T$.
By rearranging these letters,we form the word $BADMINTON$,which is the name of a game.
The first letter of the word $BADMINTON$ is $B$.
The last letter of the word $BADMINTON$ is $N$.
Therefore,the first and last letters are $B$ and $N$ respectively.

(A) The given letters are $U, S, C, A, L, A$. By rearranging these letters,we can form the meaningful word $CASUAL$. The first letter of the word $CASUAL$ is $C$.

(B) The word is $SUPERFLUOUS$.
The letters are:
$1^{st}$ letter: $S$
$4^{th}$ letter: $E$
$7^{th}$ letter: $L$
$11^{th}$ letter: $S$
The letters obtained are $S, E, L, S$.
Using these letters,we can form the word $LESS$.
The first letter of the word $LESS$ is $L$.

(A) The alphabet is $A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z$.
Counting from the right ($Z$ is 1st,$Y$ is 2nd,...):
The 6th letter from the right is $U$.
The 14th letter from the right is $M$.
Counting from the left ($A$ is 1st,$B$ is 2nd,...):
The 5th letter from the left is $E$.
The 20th letter from the left is $T$.
The letters obtained are $U, M, E, T$.
Using these letters,the meaningful word formed is $MUTE$.
The first letter of the word $MUTE$ is $M$.

(C) The word is $PERSONALITY$. The letters are indexed as follows: $P(1), E(2), R(3), S(4), O(5), N(6), A(7), L(8), I(9), T(10), Y(11)$.
The third,fourth,fifth,seventh,and tenth letters are $R, S, O, A, T$.
Using these letters $(R, S, O, A, T)$,we can form the meaningful word $ROAST$.
The first letter of the word $ROAST$ is $R$.

(B) The word is $DISTRIBUTE$.
The letters are:
1st: $D$
2nd: $I$
3rd: $S$
4th: $T$
5th: $R$
6th: $I$
7th: $B$
8th: $U$
9th: $T$
10th: $E$
The selected letters are $S, R, U, E$.
Using these letters,the meaningful word that can be formed is $SURE$.
The third letter of the word $SURE$ is $R$.

(A) The word is $ADMINISTRATION$.
The first letter is $A$.
The fourth letter is $I$.
The ninth letter is $R$.
The fourteenth letter is $N$.
The letters are $A, I, R, N$.
The meaningful word formed using these letters is $RAIN$.
The letters in $RAIN$ from left to right are $R, A, I, N$.
The third letter from the right end is $A$ (the sequence from right to left is $N, I, A, R$).

(D) The word is $CARETAKER$.
The second letter is $A$.
The fifth letter is $T$.
The eighth letter is $E$.
The letters are $A, T, E$.
Using these letters,we can form the words $ATE, EAT,$ and $TEA$.
Since more than one meaningful word can be formed,the answer is $M$.

(D) The letters of the word $'CONTRACT'$ are: $1st=C, 2nd=O, 3rd=N, 4th=T, 5th=R, 6th=A, 7th=C, 8th=T$.
The letters to be used are the $1st, 2nd, 4th, 5th,$ and $6th$ letters,which are $C, O, T, R, A$.
By rearranging these letters,we can form the meaningful word $ACTOR$.
The word $ACTOR$ has $5$ letters,and the middle letter is $T$.

(B) The word is $FELICITATIONS$.
The letters are:
1st: $F$
4th: $I$
5th: $C$
7th: $I$
10th: $T$
11th: $I$
12th: $O$
13th: $N$
Wait,let us re-index: $F(1), E(2), L(3), I(4), C(5), I(6), T(7), A(8), T(9), I(10), O(11), N(12), S(13)$.
Taking the 1st,4th,5th,7th,10th,11th,and 12th letters: $F, I, C, T, I, O, N$.
The meaningful word formed is $FICTION$.
The letters in $FICTION$ are $F, I, C, T, I, O, N$.
The fifth letter from the right end is $C$ (counting from $N(1), O(2), I(3), T(4), C(5)$).

(M) The word is $COUNTERACT$.
The letters are:
1st: $C$,2nd: $O$,3rd: $U$,4th: $N$,5th: $T$,6th: $E$,7th: $R$,8th: $A$,9th: $C$,10th: $T$.
The 4th,8th,and 10th letters are $N, A, T$.
Using these letters,we can form the words $ANT$ and $TAN$.
Since more than one meaningful word can be formed,the answer is $M$.

(D) The word is $INTERPRETATION$. The letters are:
1st: $I$
4th: $E$
7th: $R$
11th: $T$
The letters are $I, E, R, T$.
Possible meaningful words that can be formed using these letters are $TIER, RITE, TIRE$.
Since more than one word can be formed,the answer is $M$.

(A) The letters of the word $ILLOGICAL$ are: $I(1), L(2), L(3), O(4), G(5), I(6), C(7), A(8), L(9)$.
The second,fourth,fifth,and eighth letters are $L, O, G, A$.
Using these letters $(L, O, G, A)$,we can form the meaningful word $GOAL$.
Since only one meaningful word $(GOAL)$ can be formed,the third letter of this word is $A$.
Therefore,the correct option is $A$.

(D) The word is $METROPOLITAN$.
The letters are:
Second letter: $E$
Fifth letter: $O$
Tenth letter: $T$
Twelfth letter: $N$
The letters obtained are $E, O, T, N$.
Possible meaningful words that can be formed using these letters are $NOTE$ and $TONE$.
Since more than one meaningful word can be formed,the answer is $M$.

(M) The word is $PROJECTION$.
The letters at the positions are:
Third letter: $O$
Fifth letter: $E$
Seventh letter: $T$
Tenth letter: $N$
The letters are $O, E, T, N$.
Using these letters,we can form the words $NOTE$ and $TONE$.
Since more than one meaningful word can be formed,the answer is $M$.

(D) The word is $CATEGORISATION$.
The letters are:
$1^{st}: C$
$2^{nd}: A$
$3^{rd}: T$
$4^{th}: E$
$5^{th}: G$
$6^{th}: O$
$7^{th}: R$
$8^{th}: I$
$9^{th}: S$
$10^{th}: A$
$11^{th}: T$
$12^{th}: I$
$13^{th}: O$
$14^{th}: N$
The $4^{th}, 7^{th}, 11^{th}$ and $13^{th}$ letters are $E, R, T, O$.
Using these letters,we can form the words $TORE$ and $ROTE$.
Since more than one word can be formed,the answer is $M$.

(D) The word is $SEPARATION$.
The letters are:
1st letter: $S$
3rd letter: $P$
7th letter: $T$
9th letter: $O$
The letters are $S, P, T, O$.
Possible meaningful words that can be formed using these letters are $SPOT$,$POTS$,and $TOPS$.
Since more than one meaningful word can be formed,the answer is $M$.

(C) The word is $CARPENTER$. The letters available are $C, A, R, P, E, N, T, E, R$.
$1$. $NECTAR$: $N, E, C, T, A, R$ are all present in $CARPENTER$.
$2$. $CARPET$: $C, A, R, P, E, T$ are all present in $CARPENTER$.
$3$. $PAINTER$: This word requires the letter $I$. The letter $I$ is not present in $CARPENTER$.
$4$. $REPENT$: $R, E, P, E, N, T$ are all present in $CARPENTER$.
Therefore,the word $PAINTER$ cannot be formed.

(B) The given word is $TEACHERS$. The letters available are $T, E, A, C, H, E, R, S$.
$1$. $REACH$: $R, E, A, C, H$ are all present in $TEACHERS$.
$2$. $CHAIR$: The letter $I$ is not present in $TEACHERS$.
$3$. $CHEER$: $C, H, E, E, R$ are all present in $TEACHERS$.
$4$. $SEARCH$: $S, E, A, R, C, H$ are all present in $TEACHERS$.
Since the letter $I$ is not in the word $TEACHERS$,the word $CHAIR$ cannot be formed.

(A) To determine which word cannot be formed,we compare the letters in each option with the letters available in the word $CONSOLIDATE$.
The letters available in $CONSOLIDATE$ are: $C, O, N, S, O, L, I, D, A, T, E$.
$1$. $LENTIL$: $L, E, N, T, I, L$. All these letters are present in $CONSOLIDATE$.
$2$. $SLAIN$: $S, L, A, I, N$. All these letters are present in $CONSOLIDATE$.
$3$. $CONDOLE$: $C, O, N, D, O, L, E$. All these letters are present in $CONSOLIDATE$.
$4$. $DETAIL$: $D, E, T, A, I, L$. All these letters are present in $CONSOLIDATE$.
Wait,let us re-examine the letters carefully:
$CONSOLIDATE$ contains: $C(2), O(2), N(1), S(1), L(1), I(1), D(1), A(1), T(1), E(1)$.
Checking $DETAIL$: $D(1), E(1), T(1), A(1), I(1), L(1)$. All are present.
Checking $CONDOLE$: $C(1), O(2), N(1), D(1), L(1), E(1)$. All are present.
Checking $SLAIN$: $S(1), L(1), A(1), I(1), N(1)$. All are present.
Checking $LENTIL$: $L(2), E(1), N(1), T(1), I(1)$. The word $CONSOLIDATE$ only has one $L$. Therefore,$LENTIL$ cannot be formed.

(C) The given word is $UNIFORMITY$. The letters available are: $U, N, I, F, O, R, M, I, T, Y$.
Let's check each option:
$A) TINY$: $T, I, N, Y$ are all present in $UNIFORMITY$.
$B) TORN$: $T, O, R, N$ are all present in $UNIFORMITY$.
$C) RENT$: The word $RENT$ requires the letter $E$. However,the letter $E$ is not present in $UNIFORMITY$.
$D) FORM$: $F, O, R, M$ are all present in $UNIFORMITY$.
Therefore,the word $RENT$ cannot be formed.

(C) The given word is $KALEIDOSCOPE$.
The letters available in $KALEIDOSCOPE$ are: $K, A, L, E, I, D, O, S, C, P$.
Let us check each option:
$A) SCALE$: $S, C, A, L, E$ are all present in $KALEIDOSCOPE$.
$B) PADLOCK$: $P, A, D, L, O, C, K$ are all present in $KALEIDOSCOPE$.
$C) PACKET$: The letter $T$ is not present in $KALEIDOSCOPE$. Therefore,$PACKET$ cannot be formed.
$D) DIESEL$: $D, I, E, S, E, L$ are all present in $KALEIDOSCOPE$.
Thus,the correct option is $C$.

(D) The given word is $RECREATION$. The letters available are: $R, E, C, R, E, A, T, I, O, N$.
Let us check each option:
$A) RATION$: All letters $(R, A, T, I, O, N)$ are present in $RECREATION$.
$B) ACTION$: All letters $(A, C, T, I, O, N)$ are present in $RECREATION$.
$C) TORN$: All letters $(T, O, R, N)$ are present in $RECREATION$.
$D) REFER$: This word requires two $R$s,two $E$s,and one $F$. While $RECREATION$ has two $R$s and two $E$s,it does not contain the letter $F$. Therefore,$REFER$ cannot be formed.

(B) To determine which word cannot be formed,we compare the letters in the given word $SUPERIMPOSABLE$ with the letters in each option.
The letters available in $SUPERIMPOSABLE$ are: $S, U, P, E, R, I, M, P, O, S, A, B, L, E$.
$1$. $SPIRE$: All letters $(S, P, I, R, E)$ are present in $SUPERIMPOSABLE$.
$2$. $REPTILE$: The word $REPTILE$ contains the letter $T$. However,the letter $T$ is $NOT$ present in the word $SUPERIMPOSABLE$.
$3$. $POSSIBLE$: All letters $(P, O, S, S, I, B, L, E)$ are present in $SUPERIMPOSABLE$.
$4$. $REPOSURE$: All letters $(R, E, P, O, S, U, R, E)$ are present in $SUPERIMPOSABLE$.
Therefore,the word $REPTILE$ cannot be formed.

(D) The given word is $COMMENTATOR$.
The letters available are: $C, O, M, M, E, N, T, A, T, O, R$.
Let us check each option:
$A) TART$: Contains $T, A, R, T$. All these letters are present in $COMMENTATOR$.
$B) COMMON$: Contains $C, O, M, M, O, N$. All these letters are present in $COMMENTATOR$.
$C) MOMENT$: Contains $M, O, M, E, N, T$. All these letters are present in $COMMENTATOR$.
$D) COSMOS$: Contains $C, O, S, M, O, S$. The letter $S$ is not present in the word $COMMENTATOR$.
Therefore,the word $COSMOS$ cannot be formed.

(C) The given word is $MIRACULOUS$.
The letters available are: $M, I, R, A, C, U, L, O, U, S$.
Let's check each option:
$1$. $MOLAR$: $M, O, L, A, R$ are all present in $MIRACULOUS$.
$2$. $LOCUS$: $L, O, C, U, S$ are all present in $MIRACULOUS$.
$3$. $SOLACE$: This word requires the letter $E$. The letter $E$ is not present in $MIRACULOUS$.
$4$. $SCAR$: $S, C, A, R$ are all present in $MIRACULOUS$.
Therefore,the word $SOLACE$ cannot be formed.

(A) The given word is $REASONABLE$. The letters present in this word are $R, E, A, S, O, N, A, B, L, E$.
Let us check each option:
$A) BRAIN$: The letters $B, R, A, I, N$ are required. The letter $I$ is not present in $REASONABLE$. Therefore,$BRAIN$ cannot be formed.
$B) BONES$: The letters $B, O, N, E, S$ are all present in $REASONABLE$.
$C) NOBLE$: The letters $N, O, B, L, E$ are all present in $REASONABLE$.
$D) ARSON$: The letters $A, R, S, O, N$ are all present in $REASONABLE$.
Thus,the word that cannot be formed is $BRAIN$.

(D) The given word is $T R I B U N A L$.
The letters available are $T, R, I, B, U, N, A, L$.
Let us check each option:
$A) L A T I N$: All letters $(L, A, T, I, N)$ are present in $T R I B U N A L$.
$B) B R A I N$: All letters $(B, R, A, I, N)$ are present in $T R I B U N A L$.
$C) U R B A N$: All letters $(U, R, B, A, N)$ are present in $T R I B U N A L$.
$D) T R I B L E$: The letter $E$ is not present in the word $T R I B U N A L$. Therefore,the word $T R I B L E$ cannot be formed.

(D) The given word is $TEMPERAMENT$. The letters available are: $T, E, M, P, E, R, A, M, E, N, T$.
$1$. $METER$: $M, E, T, E, R$ are all present in $TEMPERAMENT$.
$2$. $TAME$: $T, A, M, E$ are all present in $TEMPERAMENT$.
$3$. $TENTER$: $T, E, N, T, E, R$ are all present in $TEMPERAMENT$.
$4$. $TESTER$: This word requires two $S$ letters. However,the word $TEMPERAMENT$ does not contain the letter $S$. Therefore,$TESTER$ cannot be formed.

(B) To determine which word cannot be formed,we compare the letters in each option with the letters available in the word $KNOWLEDGE$.
The letters available in $KNOWLEDGE$ are: $K, N, O, W, L, E, D, G, E$.
$1$. $WEDGE$: $W, E, D, G, E$ are all present in $KNOWLEDGE$.
$2$. $GODOWN$: This word requires two '$O$'s. The word $KNOWLEDGE$ contains only one '$O$'. Therefore,$GODOWN$ cannot be formed.
$3$. $KLEEN$: $K, L, E, E, N$ are all present in $KNOWLEDGE$.
$4$. $GOLDEN$: $G, O, L, D, E, N$ are all present in $KNOWLEDGE$.
Thus,the word that cannot be formed is $GODOWN$.

(C) To determine which word cannot be formed,we compare the letters in each option with the letters available in the word $CONTEMPORARY$.
The letters available in $CONTEMPORARY$ are: $C, O, N, T, E, M, P, O, R, A, R, Y$.
$1$. $PARROT$: Contains $P, A, R, R, O, T$. All these letters are present in $CONTEMPORARY$.
$2$. $COMPANY$: Contains $C, O, M, P, A, N, Y$. All these letters are present in $CONTEMPORARY$.
$3$. $CARPENTER$: Contains $C, A, R, P, E, N, T, E, R$. Note that the word $CONTEMPORARY$ has only one '$E$'. The word $CARPENTER$ requires two '$E$'s. Therefore,$CARPENTER$ cannot be formed.
$4$. $PRAYER$: Contains $P, R, A, Y, E, R$. All these letters are present in $CONTEMPORARY$.
Thus,the correct option is $C$.

(C) The given word is $REFRIGERATE$.
The letters available in the word are: $R, E, F, R, I, G, E, R, A, T, E$.
Let us analyze each option:
$A) REFER$: All letters $(R, E, F, E, R)$ are present in $REFRIGERATE$.
$B) REGRET$: All letters $(R, E, G, R, E, T)$ are present in $REFRIGERATE$.
$C) REGENERATE$: This word requires three $E$'s and two $R$'s,but it also requires two $N$'s. The letter $N$ is not present in the word $REFRIGERATE$.
$D) FREE$: All letters $(F, R, E, E)$ are present in $REFRIGERATE$.
Therefore,the word $REGENERATE$ cannot be formed.

(B) To determine which word cannot be formed,we compare the letters in each option with the letters available in the word $PARAPHERNALIA$.
The letters available in $PARAPHERNALIA$ are: $P, A, R, A, P, H, E, R, N, A, L, I, A$.
$1$. $RENAL$: $R, E, N, A, L$ are all present in $PARAPHERNALIA$.
$2$. $PRAISE$: This word contains the letter $S$. The word $PARAPHERNALIA$ does not contain the letter $S$.
$3$. $RAPHAEL$: $R, A, P, H, A, E, L$ are all present in $PARAPHERNALIA$.
$4$. $PEAR$: $P, E, A, R$ are all present in $PARAPHERNALIA$.
Therefore,the word $PRAISE$ cannot be formed.

(B) The given word is $OBSTETRICIAN$.
The letters available in $OBSTETRICIAN$ are: $O, B, S, T, E, T, R, I, C, I, A, N$.
Let us check each option:
$A) SOBER$: $S, O, B, E, R$ are all present in $OBSTETRICIAN$.
$B) TERMITE$: The word $TERMITE$ requires two $E$s. However,the word $OBSTETRICIAN$ contains only one $E$. Therefore,$TERMITE$ cannot be formed.
$C) RETAIN$: $R, E, T, A, I, N$ are all present in $OBSTETRICIAN$.
$D) SIREN$: $S, I, R, E, N$ are all present in $OBSTETRICIAN$.
Thus,the correct option is $B$.

(D) The given word is $UNCONSCIOUS$.
The letters available are: $U, N, C, O, N, S, C, I, O, U, S$.
Let us check each option:
$A) SON$: $S, O, N$ are present in $UNCONSCIOUS$.
$B) COIN$: $C, O, I, N$ are present in $UNCONSCIOUS$.
$C) SUN$: $S, U, N$ are present in $UNCONSCIOUS$.
$D) NOSE$: The letter $E$ is not present in the word $UNCONSCIOUS$.
Therefore,the word $NOSE$ cannot be formed.

(A) The given word is $TURBULENCE$. The letters available are $T, U, R, B, U, L, E, N, C, E$.
Let us check each option:
$A) CART$: $C, A, R, T$. The letter $A$ is not present in $TURBULENCE$. Therefore,$CART$ cannot be formed.
$B) BLUE$: $B, L, U, E$. All these letters are present in $TURBULENCE$.
$C) RENT$: $R, E, N, T$. All these letters are present in $TURBULENCE$.
$D) LENT$: $L, E, N, T$. All these letters are present in $TURBULENCE$.
Thus,the word that cannot be made is $CART$.

(D) The given word is $TRANQUILITY$.
The letters available in $TRANQUILITY$ are: $T, R, A, N, Q, U, I, L, I, T, Y$.
Let us check each option:
$A) QUILT$: All letters $Q, U, I, L, T$ are present in $TRANQUILITY$.
$B) TRINITY$: All letters $T, R, I, N, I, T, Y$ are present in $TRANQUILITY$.
$C) TRAIN$: All letters $T, R, A, I, N$ are present in $TRANQUILITY$.
$D) TRIANGLE$: The letter $E$ is not present in $TRANQUILITY$. Therefore,the word $TRIANGLE$ cannot be formed.
Thus,the correct option is $D$.

(B) To determine which word cannot be formed,we check the frequency of letters in the word $INTERNATIONAL$.
Letters available in $INTERNATIONAL$: $I(2), N(3), T(2), E(1), R(1), A(2), O(1), L(1)$.
Checking each option:
$A) ORIENTAL$: $O(1), R(1), I(1), E(1), N(1), T(1), A(1), L(1)$. All these letters are present in $INTERNATIONAL$.
$B) TERMINAL$: $T(1), E(1), R(1), M(1), I(1), N(1), A(1), L(1)$. The letter $M$ is $NOT$ present in $INTERNATIONAL$.
$C) LATTER$: $L(1), A(1), T(2), E(1), R(1)$. All these letters are present in $INTERNATIONAL$.
$D) RATIONALE$: $R(1), A(2), T(1), I(1), O(1), N(1), L(1), E(1)$. All these letters are present in $INTERNATIONAL$.
Since the letter $M$ is not present in the source word,$TERMINAL$ cannot be formed.

(C) To determine which word cannot be formed,we compare the letters in the given word $ORGANISATION$ with the letters in each option.
The letters available in $ORGANISATION$ are: $O, R, G, A, N, I, S, A, T, I, O, N$.
$1$. $NATION$: $N, A, T, I, O, N$ are all present in $ORGANISATION$.
$2$. $GRANT$: $G, R, A, N, T$ are all present in $ORGANISATION$.
$3$. $RECOGNISE$: This word contains the letter $E$. The word $ORGANISATION$ does not contain the letter $E$. Therefore,$RECOGNISE$ cannot be formed.
$4$. $SATAN$: $S, A, T, A, N$ are all present in $ORGANISATION$.
Thus,the correct option is $C$.