When $CH_2=CH-COOH$ is reduced with $LiAlH_4$,the compound obtained will be:

Alkene $X$ $\xrightarrow[\Delta]{KMnO_4}$ (Butan$-2-$one) $+$ (Pentanoic acid). $X$ is

Consider the following reactions:
$Ph-CH_2-CH=CH_2 \xrightarrow{H^+/H_2O} P$
$Ph-CH_2-CH=CH_2 \xrightarrow[(ii) NaBD_4]{(i) Hg(OAc)_2, H_2O} Q$
$Ph-CH_2-CH=CH_2 \xrightarrow[(ii) H_2O_2/OH^-]{(i) BD_3, THF} R$
Identify the products $P, Q$ and $R$.

Baeyer's reagent is used in the laboratory for

An alkene,on ozonolysis,gives formaldehyde and acetaldehyde. The alkene is:

In the reaction with $HCl$,an alkene reacts in accordance with the Markovnikov's rule to give a product $1-$chloro$-1-$methylcyclohexane. The possible alkene is