Zinc reacts with hydrochloric acid to give hy | vedclass

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(D) The balanced chemical equation is: $Zn(s) + 2HCl(aq) ightarrow ZnCl_2(aq) + H_2(g) \uparrow$Moles of $Zn$ used $= \frac{	ext{mass}}{	ext{molar

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The balanced chemical equation is: $Zn(s) + 2HCl(aq) ightarrow ZnCl_2(aq) + H_2(g) \uparrow$Moles of $Zn$ used $= \frac{	ext{mass}}{	ext{molar mass}} = \frac{11.5 \ g}{65.4 \ g \ mol^{-1}} \approx 0.1758 \ mol$.According to the stoichiometry of the reaction,$1 \ mol$ of $Zn$ produces $1 \ mol$ of $H_2$.Therefore,moles of $H_2$ produced $= 0.1758 \ mol$.Volume of $H_2$ at $STP = 	ext{moles} 	imes 	ext{molar volume at } STP = 0.1758 \ mol 	imes 22.7 \ L \ mol^{-1} \approx 3.99 \ L$.Rounding to the nearest integer,the volume is $4 \ L$.

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