The yellow compound $PbCrO_4$ dissolves upon treatment with a hot $NaOH$ solution. The lead-containing product formed is a:
- ATetraanionic complex with coordination number $six$
- BNeutral complex with coordination number $four$
- CDianionic complex with coordination number $six$
- DDianionic complex with coordination number $four$
Explore More
Similar Questions
Solubility of iodine in water is greatly increased by the addition of iodide ions because of the formation of ......
MediumIIT 1994
View SolutionThe complex formed during the brown ring test of nitrate $(NO_3^-)$ ion is:
Difficult
View SolutionComplex $A$ has a composition of $H_{12}O_{6}Cl_{3}Cr$. If the complex on treatment with conc. $H_{2}SO_{4}$ loses $13.5\%$ of its original mass,the correct molecular formula of $A$ is :
[Given : atomic mass of $Cr = 52 \ amu$ and $Cl = 35.5 \ amu$]
[Given : atomic mass of $Cr = 52 \ amu$ and $Cl = 35.5 \ amu$]
What is meant by stability of a coordination compound in solution? State the factors which govern stability of complexes.
Medium
View SolutionSilver chloride dissolves in
MediumAIIMS 2010
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo