Xenon reacts with fluorine at $873 \ K$ and $7 \ bar$ to form $XeF_4$. In this reaction,the ratio of xenon and fluorine required is
- A$1: 5$
- B$10: 1$
- C$1: 3$
- D$5: 1$
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Similar Questions
Match List-$I$ with List-$II$ and select the correct answer using the codes given below the lists:
List-$I$ List-$II$ $(A) \ XeF_4$ $(1) \ \text{Distorted octahedral}$ $(B) \ XeF_6$ $(2) \ \text{Tetrahedral}$ $(C) \ XeO_3$ $(3) \ \text{Square planar}$ $(D) \ XeO_4$ $(4) \ \text{Pyramidal}$
| List-$I$ | List-$II$ |
|---|---|
| $(A) \ XeF_4$ | $(1) \ \text{Distorted octahedral}$ |
| $(B) \ XeF_6$ | $(2) \ \text{Tetrahedral}$ |
| $(C) \ XeO_3$ | $(3) \ \text{Square planar}$ |
| $(D) \ XeO_4$ | $(4) \ \text{Pyramidal}$ |
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