Xenon (VI) fluoride on complete hydrolysis gi | vedclass

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(C) The complete hydrolysis of $XeF_6$ is given by the reaction:$XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF$Here,the oxide of xenon '$O$' is $XeO_3$.In the

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$6$

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(C) The complete hydrolysis of $XeF_6$ is given by the reaction:$XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF$Here,the oxide of xenon '$O$' is $XeO_3$.In the structure of $XeO_3$,the xenon atom is bonded to three oxygen atoms by double bonds $(Xe=O)$.Each $Xe=O$ bond consists of one $\sigma$ bond and one $\pi$ bond.Therefore,there are $3$ $\sigma$ bonds and $3$ $\pi$ bonds.Total number of $\sigma$ and $\pi$ bonds $= 3 + 3 = 6$.

Xenon $(VI)$ fluoride on complete hydrolysis gives an oxide of xenon '$O$'. The total number of $\sigma$ and $\pi$ bonds in '$O$' is

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