(N/A) Consider $\vec{p} = (\hat{i} + \hat{j} + \hat{k})$ and $\vec{q} = (2\hat{i} + 2\hat{j} + 2\hat{k})$.
The direction cosines of $\vec{p}$ are given by:
$l = \frac{1}{\sqrt{1^{2} + 1^{2} + 1^{2}}} = \frac{1}{\sqrt{3}}$,$m = \frac{1}{\sqrt{1^{2} + 1^{2} + 1^{2}}} = \frac{1}{\sqrt{3}}$,$n = \frac{1}{\sqrt{1^{2} + 1^{2} + 1^{2}}} = \frac{1}{\sqrt{3}}$.
The direction cosines of $\vec{q}$ are given by:
$l = \frac{2}{\sqrt{2^{2} + 2^{2} + 2^{2}}} = \frac{2}{2\sqrt{3}} = \frac{1}{\sqrt{3}}$,$m = \frac{2}{\sqrt{2^{2} + 2^{2} + 2^{2}}} = \frac{2}{2\sqrt{3}} = \frac{1}{\sqrt{3}}$,$n = \frac{2}{\sqrt{2^{2} + 2^{2} + 2^{2}}} = \frac{2}{2\sqrt{3}} = \frac{1}{\sqrt{3}}$.
Since the direction cosines of $\vec{p}$ and $\vec{q}$ are the same,the two vectors have the same direction.