Write the first three terms of the APs when a | vedclass

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(A) Given that,the first term $(a) = \sqrt{2}$ and the common difference $(d) = \frac{1}{\sqrt{2}}$.The general form of an $AP$ is $a, a+d, a+2d, \dot

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$\sqrt{2}, \frac{3}{\sqrt{2}}, \frac{4}{\sqrt{2}}$

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(A) Given that,the first term $(a) = \sqrt{2}$ and the common difference $(d) = \frac{1}{\sqrt{2}}$.The general form of an $AP$ is $a, a+d, a+2d, \dots$First term $(T_{1}) = a = \sqrt{2}$.Second term $(T_{2}) = a + d = \sqrt{2} + \frac{1}{\sqrt{2}} = \frac{(\sqrt{2} 	imes \sqrt{2}) + 1}{\sqrt{2}} = \frac{2 + 1}{\sqrt{2}} = \frac{3}{\sqrt{2}}$.Third term $(T_{3}) = a + 2d = \sqrt{2} + 2 	imes \left(\frac{1}{\sqrt{2}}ight) = \sqrt{2} + \sqrt{2} = 2\sqrt{2} = \frac{2 	imes 2}{\sqrt{2}} = \frac{4}{\sqrt{2}}$.Hence,the first three terms are $\sqrt{2}, \frac{3}{\sqrt{2}}, \frac{4}{\sqrt{2}}$.

Write the first three terms of the $APs$ when $a$ and $d$ are as given below:
$a = \sqrt{2}, d = \frac{1}{\sqrt{2}}$

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Write the first three terms of the $APs$ when $a$ and $d$ are as given below:$a = \sqrt{2}, d = \frac{1}{\sqrt{2}}$