Write the molecular formula of Marshall's acid.
- A$H_2SO_4$
- B$H_2S_2O_7$
- C$H_2S_2O_8$
- D$H_2SO_5$
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View SolutionObserve the following reactions:
$P_4 + 8SOCl_2 \longrightarrow 4PCl_3 + 4SO_2 + 2S_2Cl_2$
$P_4 + 10SO_2Cl_2 \longrightarrow 4PCl_5 + 10SO_2$
In both the reactions,a common product '$x$' is obtained. The number of lone pair of electrons on the central atom of '$x$' is:
$P_4 + 8SOCl_2 \longrightarrow 4PCl_3 + 4SO_2 + 2S_2Cl_2$
$P_4 + 10SO_2Cl_2 \longrightarrow 4PCl_5 + 10SO_2$
In both the reactions,a common product '$x$' is obtained. The number of lone pair of electrons on the central atom of '$x$' is:
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