Write the formula for the magnetic field at a perpendicular distance $r$ from a finite current-carrying wire.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) For a finite wire carrying current $I$,the magnetic field $B$ at a perpendicular distance $r$ from the wire is given by the Biot-Savart law.
If the wire subtends angles $\theta_1$ and $\theta_2$ at the point of observation with respect to the perpendicular line drawn from the point to the wire,the formula is:
$B = \frac{\mu_0 I}{4\pi r} (\sin \theta_1 + \sin \theta_2)$
where:
- $\mu_0$ is the permeability of free space.
- $I$ is the current flowing through the wire.
- $r$ is the perpendicular distance from the wire to the point.
- $\theta_1$ and $\theta_2$ are the angles subtended by the ends of the wire at the point.

Explore More

Similar Questions

It is found that a non-zero current element is unable to produce any magnetic field at a particular point. Then the angle between the current element and the position vector of that point with respect to the current element is

$A$ thin charged rod is bent into the shape of a small circle of radius $R$,the charge per unit length of the rod being $\lambda$. The circle is rotated about its axis with a time period $T$,and it is found that the magnetic field at a distance $d$ away $(d >> R)$ from the center and on the axis varies as $\frac{R^{m}}{d^{n}}$. The values of $m$ and $n$ respectively are:

An electron revolves around a nucleus with rotational frequency $f$ in a circular orbit. Due to this,the magnetic induction produced at the nucleus position is $B$. The radius of the circular orbit is directly proportional to:

$A$ straight wire of diameter $0.5\, mm$ carrying a current of $1\, A$ is replaced by another wire of $1\, mm$ diameter carrying the same current. The strength of the magnetic field at a point far away is

$A$ steady electric current is flowing through a cylindrical wire. Which of the following statements is/are correct?
$(a)$ The electric field at the axis of the wire is zero.
$(b)$ The magnetic field at the axis of the wire is zero.
$(c)$ The electric field in the vicinity of the wire is zero.
$(d)$ The magnetic field in the vicinity of the wire is zero.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo