Write the chemical formula of rust.
(N/A) The chemical formula of rust is $Fe_2O_3 \cdot xH_2O$,where $x$ represents a variable number of water molecules.
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The standard electrode potentials are given as:
$E^o_{Fe^{+2}/Fe} = -0.44 \, V$ and $E^o_{H^{+}/O_2/H_2O} = 1.23 \, V$
Calculate the $E^o_{cell}$ for the corrosion process: ............. $V$
$E^o_{Fe^{+2}/Fe} = -0.44 \, V$ and $E^o_{H^{+}/O_2/H_2O} = 1.23 \, V$
Calculate the $E^o_{cell}$ for the corrosion process: ............. $V$
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View SolutionGiven the half-cell reactions:
$2H^+ + \frac{1}{2}O_2 + 2e^- \to H_2O(l), E^o = 1.23 \ V$
$Fe^{2+} + 2e^- \to Fe(s), E^o = -0.44 \ V$
Calculate the value of $\Delta G^o$ in $kJ$ for the overall corrosion reaction.
$2H^+ + \frac{1}{2}O_2 + 2e^- \to H_2O(l), E^o = 1.23 \ V$
$Fe^{2+} + 2e^- \to Fe(s), E^o = -0.44 \ V$
Calculate the value of $\Delta G^o$ in $kJ$ for the overall corrosion reaction.
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View SolutionIron rusts in moist air because of:
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