Write the first law of thermodynamics for an isothermal process in an ideal gas.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In an isothermal process of an ideal gas,the temperature remains constant.
Since the internal energy $U$ of an ideal gas depends only on its temperature,for an isothermal process,the change in internal energy $\Delta U = 0$.
According to the first law of thermodynamics:
$\Delta Q = \Delta U + \Delta W$
Substituting $\Delta U = 0$ into the equation:
$\Delta Q = \Delta W$
This means that in an isothermal process,the entire amount of heat supplied to the system is used to perform work by the system.

Explore More

Similar Questions

An isothermal process has a non-linear graph between:

For an ideal gas, in an isothermal process:

Can the temperature of a system remain constant even when it is heated? Explain.

$A$ perfect gas of volume $5 \ L$ is compressed isothermally to a volume of $1 \ L$. The $r.m.s.$ speed of the molecules will

In an isothermal process,which statement is wrong?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo