Write the bond angle and type of hybridization of the water molecule.
(N/A) In a water molecule $(H_2O)$,the oxygen atom is $sp^3$ hybridized.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
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Similar Questions
Define the following terms:
$(i)$ Hybridisation
$(ii)$ $sp$ Hybridisation
$(iii)$ $sp^2$ Hybridisation
$(iv)$ $sp^3$ Hybridisation
$(v)$ Hydrogen bonding
$(i)$ Hybridisation
$(ii)$ $sp$ Hybridisation
$(iii)$ $sp^2$ Hybridisation
$(iv)$ $sp^3$ Hybridisation
$(v)$ Hydrogen bonding
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Chlorine atom,in its third excited state,reacts with fluorine to form a compound $X$. The formula and shape of $X$ are :
Match the compounds given in $Column\, I$ with the hybridisation and shape given in $Column\, II$ and mark the correct option.
$Column\, I$ $Column\, II$ $(A)\, XeF_6$ $(i)\, \text{Distorted octahedral}$ $(B)\, XeO_3$ $(ii)\, \text{Square planar}$ $(C)\, XeOF_4$ $(iii)\, \text{Pyramidal}$ $(D)\, XeF_4$ $(iv)\, \text{Square pyramidal}$
| $Column\, I$ | $Column\, II$ |
|---|---|
| $(A)\, XeF_6$ | $(i)\, \text{Distorted octahedral}$ |
| $(B)\, XeO_3$ | $(ii)\, \text{Square planar}$ |
| $(C)\, XeOF_4$ | $(iii)\, \text{Pyramidal}$ |
| $(D)\, XeF_4$ | $(iv)\, \text{Square pyramidal}$ |
MediumNEET 2016
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