Work done when 2 mol of an ideal gas is comp | vedclass

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(A) The work done during the compression of a gas against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. Given: $P_{ex

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$250$

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(A) The work done during the compression of a gas against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. Given: $P_{ext} = 100 \ kPa = 10^{5} \ Pa$ $V_{initial} = 5 \ m^{3}$ $V_{final} = 2.5 \ m^{3}$ $\Delta V = V_{final} - V_{initial} = 2.5 \ m^{3} - 5 \ m^{3} = -2.5 \ m^{3}$ Substituting the values: $W = -(10^{5} \ Pa) 	imes (-2.5 \ m^{3})$ $W = 2.5 	imes 10^{5} \ J$ $W = 250,000 \ J = 250 \ kJ$. Since the gas is compressed, work is done on the system, resulting in a positive value.

Work done when $2 \ mol$ of an ideal gas is compressed from a volume of $5 \ m^{3}$ to $2.5 \ m^{3}$ at $300 \ K$, under a constant external pressure of $100 \ kPa$ is: (in $kJ$)

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