With reference to the observations in photoel | vedclass

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(B) According to Einstein's photoelectric equation: $\frac{1}{2}mv_{\max}^2 = hf - \phi$. Since $\frac{1}{2}mv_{\max}^2 = K_{\max}$,we have $K_{\max}

Vedclass · Accepted Answer

$A$ and $E$ only

Vedclass · Answer

(B) According to Einstein's photoelectric equation: $\frac{1}{2}mv_{\max}^2 = hf - \phi$. Since $\frac{1}{2}mv_{\max}^2 = K_{\max}$,we have $K_{\max} = hf - \phi$. Thus,$v_{\max}^2$ varies linearly with frequency $f$. Statement $A$ is correct.Saturation current depends on the intensity of light. Moving the source away decreases intensity,thus decreasing saturation current. Statement $B$ is incorrect.Maximum kinetic energy depends on the frequency of incident light,not the power (intensity). Statement $C$ is incorrect.Immediate emission is explained by the particle nature of light (photon interaction),not the wave nature. Statement $D$ is incorrect.Wave theory predicts that emission should occur for any frequency if intensity is high enough,which contradicts the existence of a threshold wavelength. Statement $E$ is correct.Therefore,statements $A$ and $E$ are correct.

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