Why does a child feel more pain when she falls down on a hard cement floor,than when she falls on the soft muddy ground in the garden?

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(N/A) According to Newton's Second Law of Motion,the force $F$ exerted on an object is given by the rate of change of momentum: $F = \frac{\Delta p}{\Delta t}$.
When a child falls on a hard cement floor,the time interval $\Delta t$ for the change in momentum to become zero is very small. Since $F \propto \frac{1}{\Delta t}$,a smaller time interval results in a larger impulsive force,causing more pain.
Conversely,when a child falls on soft muddy ground,the ground yields,increasing the time interval $\Delta t$ over which the momentum changes. $A$ larger time interval results in a smaller force,thereby reducing the pain felt by the child.

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