Why does (second)$^{2}$ occur in the unit of acceleration ?
Why does (second)$^{2}$ occur in the unit of acceleration ?
Acceleration $=\frac{\text { Change in velocity }}{\text { Time taken }}$
Unit of velocity and time is metre per second and second respectively. So Unit of acceleration
$=\frac{m s^{-1}}{s}=m s^{-2}$
Similar Questions
All buses and cars these days are fitted with a speedometer, which shows the velocity of the vehicle. A device called odometer records the distance moved by the vehicle. If the reading on the odometer of a vehicle in the beginning of a trip and after $40$ minutes were $1048\, km$ and $1096\, km$ respectively, calculate its average velocity. Will the reading on the speedometer show this velocity when the vehicle is moving ? Support your answer with reason.
All buses and cars these days are fitted with a speedometer, which shows the velocity of the vehicle. A device called odometer records the distance moved by the vehicle. If the reading on the odometer of a vehicle in the beginning of a trip and after $40$ minutes were $1048\, km$ and $1096\, km$ respectively, calculate its average velocity. Will the reading on the speedometer show this velocity when the vehicle is moving ? Support your answer with reason.
The direction of acceleration of an object moving in a circular path is
The direction of acceleration of an object moving in a circular path is
What does the slope of velocity$-$time graph represent ?
What does the slope of velocity$-$time graph represent ?
Derive the equation $v^{2}-u^{2}=2 a S$ graphically.
Derive the equation $v^{2}-u^{2}=2 a S$ graphically.
Area under velocity$-$time graph is equal to the
Area under velocity$-$time graph is equal to the