Why does a body weigh more at the poles than at the equator?

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(N/A) The acceleration due to gravity $(g)$ is given by the formula $g = GM/R^2$,where $R$ is the radius of the Earth.
Because the Earth is not a perfect sphere but is flattened at the poles and bulges at the equator,the radius at the poles $(R_p)$ is less than the radius at the equator $(R_e)$.
Since $g$ is inversely proportional to the square of the radius $(g \propto 1/R^2)$,a smaller radius at the poles results in a higher value of $g$ $(g_p > g_e)$.
Weight is defined as $W = mg$. Since the mass $(m)$ of the body remains constant and $g_p > g_e$,it follows that $mg_p > mg_e$.
Therefore,a body weighs more at the poles than at the equator.

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