White phosphorus reacts with caustic soda. Th | vedclass

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(C) The chemical reaction is: $P_4 + 3NaOH + 3H_2O \rightarrow PH_3 + 3NaH_2PO_2$. In this reaction,the oxidation state of phosphorus changes from $0$

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Oxidation and reduction

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(C) The chemical reaction is: $P_4 + 3NaOH + 3H_2O \rightarrow PH_3 + 3NaH_2PO_2$. In this reaction,the oxidation state of phosphorus changes from $0$ in $P_4$ to $-3$ in $PH_3$ (reduction) and to $+1$ in $NaH_2PO_2$ (oxidation). Since the same element is simultaneously oxidized and reduced,this is a disproportionation reaction,which is a type of redox reaction involving both oxidation and reduction.

White phosphorus reacts with caustic soda. The products are $PH_3$ and $NaH_2PO_2$. This reaction is an example of

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Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$P_4 + 3NaOH + 3H_2O \longrightarrow PH_3 + 3NaH_2PO_2$
(Note: The reaction provided is the standard balanced equation for the disproportionation of white phosphorus.)

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