Which statement is correct about CO_2 if the | vedclass

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(B) In $CO_2$,the carbon atom is $sp$ hybridized.If the central carbon atom uses $s$ and $P_x$ orbitals for hybridization,the hybrid orbitals lie alon

Vedclass · Accepted Answer

$i, ii, iii$

Vedclass · Answer

(B) In $CO_2$,the carbon atom is $sp$ hybridized.If the central carbon atom uses $s$ and $P_x$ orbitals for hybridization,the hybrid orbitals lie along the $x$-axis.Consequently,the $\pi$ bonds are formed by the remaining unhybridized $P_y$ and $P_z$ orbitals.This satisfies statement $(i)$.Since the hybrid orbitals are along the $x$-axis,the molecule can lie in any plane containing the $x$-axis,such as the $XY$ plane (statement $ii$) or the $XZ$ plane (statement $iii$).It cannot lie in the $YZ$ plane because the $x$-axis is perpendicular to the $YZ$ plane.Thus,the correct statements are $(i)$,$(ii)$,and $(iii)$.

Similar Questions

Consider the following reactions:
$(i)$ $PCl_3 + 3H_2O \to H_3PO_3 + 3HCl$
$(ii)$ $SF_4 + 3H_2O \to H_2SO_3 + 4HF$
$(iii)$ $BCl_3 + 3H_2O \to H_3BO_3 + 3HCl$
$(iv)$ $XeF_6 + 3H_2O \to XeO_3 + 6HF$
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