Which statement about the following equilibri | vedclass

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(A) The equilibrium reaction is: $(CH_3)_3CO^- + H_2O \rightleftharpoons (CH_3)_3COH + OH^-$.Acid-base reactions always proceed in the direction of fo

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The equilibrium favours the products.

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(A) The equilibrium reaction is: $(CH_3)_3CO^- + H_2O \rightleftharpoons (CH_3)_3COH + OH^-$.Acid-base reactions always proceed in the direction of forming the weaker acid and the weaker base.Comparing the $pK_a$ values: $H_2O$ $(pK_a = 15.7)$ is a stronger acid than $(CH_3)_3COH$ $(pK_a = 18)$.Since the reaction proceeds from the stronger acid to the weaker acid,the equilibrium lies to the right (towards the products).Therefore,$(CH_3)_3CO^-$ is a stronger base than $OH^-$,and the equilibrium favours the formation of the weaker base $(OH^-)$ and the weaker acid $((CH_3)_3COH)$.Thus,$t$-butoxide is the dominant anionic species is incorrect,and the equilibrium favours the products.

Which statement about the following equilibrium is true?
$(CH_3)_3CO^-K^+ + H_2O \rightleftharpoons (CH_3)_3COH + K^+OH^-$
Given: $pK_a(H_2O) = 15.7$,$pK_a((CH_3)_3COH) = 18$

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Which statement about the following equilibrium is true?$(CH_3)_3CO^-K^+ + H_2O \rightleftharpoons (CH_3)_3COH + K^+OH^-$Given: $pK_a(H_2O) = 15.7$,$pK_a((CH_3)_3COH) = 18$