Which solution will be basic?

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Question

(B) solution is basic if its $pH > 7$. The $pH$ is calculated using the formula $pH = -\log[H_{3}O^{+}]$. For option $A$: $pH = -\log(10^{-5}) = 5$ (A

Vedclass · Accepted Answer

$[H_{3}O^{+}] = 10^{-12} \; M$

Vedclass · Answer

(B) solution is basic if its $pH > 7$. The $pH$ is calculated using the formula $pH = -\log[H_{3}O^{+}]$. For option $A$: $pH = -\log(10^{-5}) = 5$ (Acidic). For option $B$: $pH = -\log(10^{-12}) = 12$ (Basic). For option $C$: $pH = -\log(10^{-7}) = 7$ (Neutral). For option $D$: $pH = -\log(10^{-4}) = 4$ (Acidic). Since $12 > 7$,the solution with $[H_{3}O^{+}] = 10^{-12} \; M$ is basic.

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