(B) In a faintly alkaline or neutral medium,the permanganate ion $(MnO_4^-)$ acts as an oxidizing agent and oxidizes the iodide ion $(I^-)$ to the iod

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(B) In a faintly alkaline or neutral medium,the permanganate ion $(MnO_4^-)$ acts as an oxidizing agent and oxidizes the iodide ion $(I^-)$ to the iodate ion $(IO_3^-)$.The balanced chemical equation for this reaction is:$2MnO_4^- + I^- + H_2O \rightarrow 2MnO_2 + IO_3^- + 2OH^-$Therefore,the product obtained is $IO_3^-$.

Class 11 Chemistry Redox Reactions Redox reaction and Method for balancing Redox reaction

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Which product is obtained during the reaction of $MnO_4^-$ with $I^-$ in a faintly alkaline condition?

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A
$I_2$
B
$IO_3^-$
C
$IO^-$
D
$IO_4^-$

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Redox Reactions

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Redox reaction and Method for balancing Redox reaction

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Which product is obtained during the reaction of $MnO_4^-$ with $I^-$ in a faintly alkaline condition?

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