Which product is formed when the compound $C_6H_5CHO$ is treated with concentrated $KOH$ solution?

Which of the following is obtained when chloral is boiled with $NaOH$?

Which one of the following undergoes reaction with $50\% \, NaOH$ solution to give the corresponding alcohol and acid?

Given below are two statements:
Statement $I$: $H_2N-CO-CH_2-CH_2-CO-CH_3$ under Clemmensen reduction conditions will give $HOOC-(CH_2)_3-CH_3$.
Statement $II$: $CH_3-CH(CH_3)-CH_2-CH(Cl)-CO-CH_3$ under Wolff-Kishner reduction conditions will give $CH_3-CH(CH_3)-CH_2-CH(Cl)-CH_2-CH_3$.
In the light of the above statements,choose the correct answer from the options given below:

Compound $A$ $(C_9H_{10}O)$ shows a positive iodoform test. Oxidation of $A$ with $KMnO_4/KOH$ gives acid $B$ $(C_8H_6O_4)$. The anhydride of $B$ is used for the preparation of phenolphthalein. Compound $A$ is:

An organic compound $(X)$ with molecular formula $C_3H_6O$ is not readily oxidised. On reduction it gives $(C_3H_8O)$ $(Y)$ which reacts with $HBr$ to give a bromide $(Z)$ which is converted to a Grignard reagent. This Grignard reagent on reaction with $(X)$ followed by hydrolysis gives $2,3-$dimethylbutan$-2-$ol. Compounds $(X)$,$(Y)$ and $(Z)$ respectively are $:$