Which pair of elements has the maximum electronegativity difference?

Given below are two statements:
Statement $I$: The correct order of electronegativity of fluorine,oxygen and nitrogen is $F > O > N$.
Statement $II$: The oxidation state of oxygen in $OF_2$ is $+2$ and in $Na_2O$ is $-2$.

Among $Me_{3}N$,$C_{5}H_{5}N$ and $MeCN$ $(Me = \text{methyl group})$,the electronegativity of $N$ is in the order:

If the ionization enthalpy and electron gain enthalpy of an element are $275$ and $86 \ kcal \ mol^{-1}$ respectively,then the electronegativity of the element on the Pauling scale is

The $EN$ (Electronegativity) of element $A$ is $E_1$ and its $IP$ (Ionization Potential) is $E_2$. Hence,the $EA$ (Electron Affinity) will be:

For $AB$ bond,if percent ionic character is plotted against electronegativity difference $(X_A - X_B)$,the shape of the curve would look like. The correct curve is: