(D) $N_2O_5$ is the anhydride of $HNO_3$.$2HNO_3 \to N_2O_5 + H_2O$In $N_2O_5$,the oxidation state of nitrogen is $+5$,which is the maximum possible o

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(D) $N_2O_5$ is the anhydride of $HNO_3$.$2HNO_3 \to N_2O_5 + H_2O$In $N_2O_5$,the oxidation state of nitrogen is $+5$,which is the maximum possible oxidation state for nitrogen. Therefore,it cannot be oxidized further and can only act as an oxidizing agent.