Which order is correct for the decreasing rea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Ring monobromination is an electrophilic aromatic substitution reaction.The reactivity of the benzene ring depends on the nature of the substituen

Vedclass · Accepted Answer

$I > III > II > IV$

Vedclass · Answer

(B) Ring monobromination is an electrophilic aromatic substitution reaction.The reactivity of the benzene ring depends on the nature of the substituent group.Activating groups (electron-donating groups like $-CH_3$) increase the electron density on the ring and increase reactivity,while deactivating groups (electron-withdrawing groups like $-COOH$ and $-NO_2$) decrease the electron density and decrease reactivity.Benzene $(III)$ is more reactive than rings with deactivating groups but less reactive than rings with activating groups.Among the deactivating groups,$-NO_2$ is more strongly deactivating than $-COOH$.Therefore,the correct decreasing order of reactivity is: $C_6H_5CH_3$ $(I)$ > $C_6H_6$ $(III)$ > $C_6H_5COOH$ $(II)$ > $C_6H_5NO_2$ $(IV)$.

Which order is correct for the decreasing reactivity to ring monobromination of the following compounds: $C_6H_5CH_3$ $(I)$,$C_6H_5COOH$ $(II)$,$C_6H_6$ $(III)$,and $C_6H_5NO_2$ $(IV)$?

Similar Questions

Statement-$I$: Benzene gives Friedel-Crafts reaction.
Statement-$II$: All substituted benzenes give Friedel-Crafts reaction.
Choose the correct statement:

Why does benzene undergo electrophilic substitution reactions easily and nucleophilic substitutions with difficulty?

Which position will be attacked most rapidly by the nitronium ion $(NO_2)^+$ when the compound undergoes nitration with $HNO_3 / H_2SO_4$?

Which of the following are not aromatic?

The major product of the following reaction is:
$Glucose \xrightarrow[(ii) \ Mo_2O_3, \ 773 \ K, \ 10-20 \ atm]{(i) \ HI, \ \Delta} ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module