Which optically active compound on reduction | vedclass

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Question

(C) $LiAlH_4$ reduces the carboxylic acid group $(-COOH)$ to a primary alcohol group $(-CH_2OH)$.In option $(C)$,the starting material is $CH_3-CH_2-C

Vedclass · Accepted Answer

$CH_3-CH_2-CH(CH_2OH)-COOH$

Vedclass · Answer

(C) $LiAlH_4$ reduces the carboxylic acid group $(-COOH)$ to a primary alcohol group $(-CH_2OH)$.In option $(C)$,the starting material is $CH_3-CH_2-CH(CH_2OH)-COOH$. Upon reduction,it forms $CH_3-CH_2-CH(CH_2OH)-CH_2OH$,which can be written as $CH_3-CH_2-CH(CH_2OH)_2$.In this product,the central carbon atom is attached to two identical $-CH_2OH$ groups,making the molecule achiral and thus optically inactive.

Which optically active compound on reduction with $LiAlH_4$ will give an optically inactive compound?

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